-2
0
1
2
Correct answer is B
To find the maximum value, we can use the second derivative test where, given \(f(x)\), the second derivative < 0, makes it a maximum value.
\(x(x + 1)^{2} = x(x^{2} + 2x + 1) = x^{3} + 2x^{2} + x\)
\(\frac{\mathrm d y}{\mathrm d x} = 3x^{2} + 4x + 1 = 0\)
Solving, we have \( x = \frac{-1}{3}\) or \(-1\).
\(\frac{\mathrm d^{2} y}{\mathrm d x^{2}} = 6x + 4\)
When \(x = \frac{-1}{3}, \frac{\mathrm d^{2} y}{\mathrm d x^{2}} = 2 > 0\)
When \(x = -1, \frac{\mathrm d^{2} y}{\mathrm d x^{2}} = -2 < 0\)
At maximum value of x being -1, \(y = -1(-1 + 1)^{2} = 0\)
Evaluate \(\int_{\frac{1}{2}}^{1} \frac{x^{3} - 4}{x^{3}} \mathrm {d} x\)....
Find the inverse of \(\begin{pmatrix} 3 & 5 \\ 1 & 2 \end{pmatrix}\)...
Find the minimum value of \(y = 3x^{2} - x - 6\)....
Marks 2 3 4 5 6 7 8 No of students 5 7 9 6 3 6 4 The table above sho...
Evaluate \(\int_{1}^{2} (2 + 2x - 3x^{2}) \mathrm {d} x\)....
The remainder when \(x^{3} - 2x + m\) is divided by \(x - 1\) is equal to the remainder when \...
A force of 230N acts in its direction 065\(^o\). Find its horizontal component....