0
1
7
13
Correct answer is D
\lim\limits_{x \to 3} \frac{2x^{2} + x - 21}{x - 3}
2x^{2} + x - 21 = 2x^{2} - 6x + 7x - 21 (by factorizing)
= (2x + 7)(x - 3)
\therefore \lim\limits_{x \to 3} \frac{2x^{2} + x - 21}{x - 3} \equiv \lim\limits_{x \to 3} \frac{(2x+7)(x-3)}{x-3}
\lim\limits_{x \to 3} (2x + 7) = 2(3) + 7 = 13
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