x2+10x+c
x+53x3+x4+c
x−5x2−2x3+c
x−5x−12x2+c
Correct answer is D
x3+5x+1x3≡1+5x2+1x3
≡∫(1+5x2+1x3)dx=∫(1+5x−2+x−3)dx
= (x−5x−1−12x−2+c)
= x−5x−12x2+c.
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