1.7N
4.5N
9.0N
13.0N
Correct answer is A
F = F \cos \theta + F \sin \theta
where F \cos \theta = \text{horizontal component}
F \sin \theta = \text{vertical component}
Horizontal component of resultant = sum of horizontal compoents of individual forces
= 8 \cos 30 + 10 \cos 150 = 6.928 - 8.66 \approxeq - 1.7N
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