3
2
-2
-3
Correct answer is D
The sum of deviations from the mean of a set of numbers equals 0.
(k+3)2+(k+7)+(−2)+k+(k+2)2=0
(k2+6k+9)+(k+7)−2+k+(k2+4k+4)=0
2k2+12k+18=0
2k2+6k+6k+18=2k(k+3)+6(k+3)=0
k=−3(twice)
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