\frac{7}{2}
0
\frac{-7}{2}
-7
Correct answer is A
\lim\limits_{x \to 3} (\frac{x^{3} + x^{2} - 12x}{x^{2} - 9}) = \lim\limits_{x \to 3} (\frac{x^{3} - 3x^{2} + 4x^{2} - 12x}{(x - 3)(x + 3)}
\lim\limits_{x \to 3} (\frac{(x^{2} + 4x)(x - 3)}{(x - 3)(x + 3)} = \lim\limits_{x \to 3} (\frac{x^{2} + 4x}{x + 3})
=\frac{3^{2} + 4(3)}{3 + 3} = \frac{21}{6} = \frac{7}{2}
Given that sin x = \frac{4}{5} and cos y = \frac{12}{13}, where x is an obtuse angle and y i...
The mean and median of integers x, y, z and t are 5 and z respectively. If x < y < z < t an...
Find the distance between the points (2, 5) and (5, 9). ...
Find the value of p for which x^{2} - x + p becomes a perfect square. ...
Determine the coefficient of x^{2} in the expansion of (a + 3x)^{6}...
Solve the inequality 2x^{2} + 5x - 3 \geq 0....
In a firing contest, the probabilities that Kojo and Kwame hit the target are \frac{2}{5} and \(...
If the binomial expansion of (1 + 3x)^6 is used to evaluate (0.97)^6, find the value of x.&n...