(x - 3)(x - 2)(2x + 2)
(x + 3)(x - 2)(x - 1)
(x - 3)(x + 2)(2x -1)
(x + 3)(x - 2)(2x - 1)
Correct answer is C
Since f(3) = 0, then (x - 3) is a factor of f(x).
Dividing f(x) by (x - 3), we get 2x2+3x−2.
2x2+3x−2=2x2−x+4x−2
x(2x−1)+2(2x−1)=(x+2)(2x−1)
Therefore, f(x)=(x−3)(x+2)(2x−1)
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