1
\frac{1}{2}
0
-1
Correct answer is A
\lim \limits_{x \to 1} \frac{1 - x}{x^{2} - 3x + 2}
\frac{1 - x}{x^{2} - 3x + 2} = \frac{-(x - 1)}{(x - 1)(x - 2)}
= \frac{-1}{x - 2}
\lim \limits_{x \to 1} \frac{1 - x}{x^{2} - 3x + 2} = \lim \limits_{x \to 1} \frac{-1}{x - 2}
= \frac{-1}{1 - 2} = \frac{-1}{-1} = 1
The sum, S_{n}, of a sequence is given by S_{n} = 2n^{2} - 5. Find the 6th term...
If \overrightarrow{OA} = 3i + 4j and \overrightarrow{OB} = 5i - 6j where O is the origin an...
Find the coordinates of the centre of the circle 3x^2 + 3y^2 - 6x + 9y - 5 = 0...
Find the constant term in the binomial expansion (2x^{2} + \frac{1}{x})^{9}...
For what value of k is 4x^2 - 12x + k, a perfect square?...
A binary operation * is defined on the set of real number, R, by x*y = x^2 - y^2 + xy, where...
Simplify \frac{\sqrt{3}}{\sqrt{3} - 1} + \frac{\sqrt{3}}{\sqrt{3} +1}...
Find the coefficient of x^3y^2 in the binomial expansion of (x-2y)^5...