(x+3)and(x−2)
(x−3)and(x+2)
(x−3)and(x−2)
(x+3)and(x+2)
Correct answer is A
(x - 5) is a factor of x3−4x2−11x+30. To find the remaining factors, let's draw out (x−5) from the parent expression.
x3−4x2−11x+30=x3−5x2+x2−5x−6x+30
=x2(x−5)+x(x−5)−6(x−5)=(x−5)(x2+x−6)
∴ To find the remaining factors, we factorize (x2+x−6)
x2+x−6=x2+3x−2x−6
=x(x+3)−2(x+3)=(x+3)(x−2)
∴ The other two factors are (x+3)and(x−2)
ALTERNATIVELY
∴ x^2 + x - 6 = (x + 3) and (x - 2)
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