x2−y2−6x+16y+23=0
x2+y2+6x+16y−23=0
x2+y2+6x−16y+23=0
x2+y2−6x+16y+23=0
Correct answer is B
Equation of a circle: (x−a)2+(y−b)2=r2
where (a, b) and r are the coordinates of the centre and radius respectively.
Given : (a,b)=(−3,−8);r=4√6
(x−(−3))2+(y−(−8))2=(4√6)2
x2+6x+9+y2+16y+64=96
x2+y2+6x+16y+9+64−96=0
⟹x2+y2+6x+16y−23=0