1
12
512
112
Correct answer is C
p(P)=12,p(P′)=12
p(Q)=13,p(Q′)=23
p(R)=34,p(R′)=14
p(exactly two hit the target) = p(P and Q and R') + p(P and R and Q') + p(Q and R and P')
= (12×13×14)+(12×34×23)+(13×34×12)
= 124+624+324
= 512
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