4
3
2
0
Correct answer is A
\lim \limits_{x \to 3} \frac{x^{2} - 2x - 3}{x - 3}
\frac{x^{2} - 2x - 3}{x - 3} = \frac{x^{2} - 3x + x - 3}{x - 3}
\frac{(x - 3)(x + 1)}{x - 3} = x + 1
\lim \limits_{x \to 3} \frac{x^{2} - 2x - 3}{x - 3} \equiv \lim \limits_{x \to 3} (x + 1) (L'Hopital rule)
\lim \limits_{x \to 3} (x + 1) = 3 + 1 = 4
A function is defined by f(x) = \frac{3x + 1}{x^{2} - 1}, x \neq \pm 1. Find f(-3)....
Calculate the standard deviation of 30, 29, 25, 28, 32 and 24. ...
If s = 3i - j and t = 2i + 3j, find (t - 3s).(t + 3s)....
If log_{y}\frac{1}{8} = 3, find the value of y....
If \begin{pmatrix} 2 & 1 \\ 4 & 3 \end{pmatrix}\(\begin{pmatrix}...
Consider the following statement: x: All wrestlers are strong y: Some wresters are not weightl...
If \overrightarrow{OX} = \begin{pmatrix} -7 \\ 6 \end{pmatrix} and \(\overrightarrow{OY} = \begi...