Find the locus of points which is equidistant from P(4, 5...
Find the locus of points which is equidistant from P(4, 5) and Q(-6, -1).
3x - 5y + 13 = 0
3x - 5y - 7 = 0
5x - 3y + 7 = 0
5x + 3y - 1 = 0
Correct answer is D
Midpoint between P(4, 5) and Q(-6, -1) = 4−62,5−12=(−1,2)
Gradient of PQ = 5−(−1)4−(−6)=35
Gradient of line perpendicular to PQ = −135=−53
line=y−2x+1=−53
3y−6=−5x−5
5x+3y−6+5=0⟹5x+3y−1=0
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