18.75 N
15.75 N
9.50 N
8.66 N
Correct answer is D
\(F_{1} = (5 N, 060°) = 5 \cos 60 i + 5 \sin 60 j = 2.5 i + \frac{5\sqrt{3}}{2}j\)
\(F_{2} = (10 N, 180°) = 10 \cos 180 i + 10 \sin 180 j = -10i\)
\(R = F_{1} + F_{2} = -7.5 i + \frac{5\sqrt{3}}{2}j\)
\(|R| = \sqrt{(-7.5)^{2} + (\frac{5\sqrt{3}}{2})^{2}}\)
= \(\sqrt{56.25 + 18.75} = \sqrt{75}\)
= 8.66 N
If \(\sin\theta = \frac{3}{5}, 0° < \theta < 90°\), evaluate \(\cos(180 - \theta)\)....
From the diagram above, \(h[g(3)]\) is...
Given that \(^{n}P_{r} = 90\) and \(^{n}C_{r} = 15\), find the value of r....
A force 10N acts in the direction 060° and another force 6N acts in the direction 330°. Find...
If →PQ = -2i + 5j and →RQ = -i - 7j, find →PR ...
If (2t - 3s)(t - s) = 0, find \(\frac{t}{s}\)...
Two forces \(F_{1} = (10N, 020°)\) and \(F_{2} = (7N, 200°)\) act on a particle. Find the re...