A particle is projected vertically upwards with a speed of 40 m/s. At what times will it be 35m above its point of projection? $\text{Take g} = 10 ms^{-2}$

Similar Questions

An operation * is defined on the set, R, of real numbers by $p * q = p + q + 2pq$. If the identity...

A particle starts from rest and moves in a straight line such that its acceleration after t secs is ...

The initial velocity of an object is $u = \begin{pmatrix} -5 \\ 3 \end{pmatrix} ms^{-1}$. If the a...

Evaluate \(\begin{pmatrix} 2 & 3 \\ 4 & 1 \end{pmatrix} \begin{pmatrix} 2 \\ 3 \end{pmatrix}...

The distance S metres moved by a body in t seconds is given by \(S = 5t^3 - \frac{19}{2} t^2 + 6t - ...

Simplify $\sqrt{(\frac{-1}{64})^{\frac{-2}{3}}}$...

In how many ways can the letters of the word 'ELECTIVE' be arranged? ...

Find $\lim\limits_{x \to 3} \frac{2x^{2} + x - 21}{x - 3}$....

Find the coordinates of the point which divides the line joining P(-2, 3) and Q(4, 6) internally in ...

Simplify $2\log_{3} 8 - 3\log_{3} 2$...