\({\color{red}2x} \times 3\)
1 - \(\sqrt{6}\)
\(\sqrt{6}\) - 1
\(\sqrt{6}\)
1 + \(\sqrt{6}\)
Correct answer is D
x*y = x\(^2\) - y\(^2\) + xy
(\(\sqrt{3}\))*(\(\sqrt{2}\)) = (\(\sqrt{3}\))\(^2\) - (\(\sqrt{2}\))\(^2\) + \(\sqrt{3}\) x \(\sqrt{2}\)
= 3 - 2 + \(\sqrt{6}\)
= 1 + \(\sqrt{6}\)
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