1−12√3
1+12√3
√3
1+√3
Correct answer is B
1(1−√3)2
(1−√3)2=(1−√3)(1−√3)
1−2√3+3=4−2√3
14−2√3
After rationalising (multiplying the denominator and numerator with 4+2√3, we have
4+2√34=1+12√3
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