8πcm2s−1
16πcm2s−1
24πcm2s−1
48πcm2s−1
Correct answer is D
Surface area of sphere, A=4πr2
dAdr=8πr
The rate of change of radius with time drdt=3cms−1
dAdt=(dAdr)(drdt)
= 8π×2cm×3cms−1=48πcm2s−1
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