±12
±3
±4
±6
Correct answer is A
The general form of a quadratic equation is:
x2-(sum of roots) = 0
For equal roots it's:x^2 - 2(α)+(α)^2=0
3x^2+px+12=0
Divide through by 3
= x^2+\frac{p}{3}x+4=0
=x^2-(-\frac{p}{3})x+4=0
So,α^2=4
= α = √4 = ±2
Also,-\frac{p}{3}= 2α
When α = 2
-\frac{p}{3} = 2(2)=4
=p=-12
When α =-2
-\frac{p}{3}=2(-2)=-4
= p = 12
∴ values of p = ±12
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