30o and 150o
150o and 210o
210o and 330o
150o and 330o
Correct answer is C
sin θ = -1/2 = -0.5 θ = sin-1 (0.5) θ = 30o Since θ is negative θ = 180 + 30 = 210o θ = 360 - 30 = 330o ∴θ = 210o and 330o
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