If x = {n $^2$ +1:n is a positive integer and 1 $\leq$ n $\leq$ 5},
Y = {5n:n is a positive integer and 1 $\leq$ n $\leq$ 5}, find x $\cap$ y.

{5,10}

{5, 10, 15}

{2, 5, 10}

{5, 10, 15, 20}

Correct answer is A

X = {n(^2\)+1:n is a positive integer and 1 $\leq$ n $\leq$ 5}
Implies X = {2, 5, 10, 17, 26} i.e. put n= 1, 2, 3, 4 and 5
Y = {5n:n is a positive integer and 1 $\leq$ n $\leq$ 5}
Put X = 1, 2, 3, 4, and 5
Y = {5, 10, 15, 20, 25}
X $\cap$ Y = {2, 5, 10, 17, 26} $\cap$ {5, 10, 15, 20, 25}
= {5, 10}

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