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If x = {n\(^2\)+1:n is a positive integer and 1 \(\leq\) n \...

If x = {n\(^2\)+1:n is a positive integer and 1 \(\leq\) n \(\leq\) 5},
Y = {5n:n is a positive integer and 1 \(\leq\) n \(\leq\) 5}, find x \(\cap\) y.

A.

{5,10}

B.

{5, 10, 15}

C.

{2, 5, 10}

D.

{5, 10, 15, 20}

Correct answer is A

X = {n(^2\)+1:n is a positive integer and 1 \(\leq\) n \(\leq\) 5}
Implies X = {2, 5, 10, 17, 26} i.e. put n= 1, 2, 3, 4 and 5
Y = {5n:n is a positive integer and 1 \(\leq\) n \(\leq\) 5}
Put X = 1, 2, 3, 4, and 5
Y = {5, 10, 15, 20, 25}
X \(\cap\) Y = {2, 5, 10, 17, 26} \(\cap\) {5, 10, 15, 20, 25}
= {5, 10}