In the diagram above, ∠PTQ = ∠URP = 25° ...
In the diagram above, ∠PTQ = ∠URP = 25° and XPU = 4URP. Calculate ∠USQ.
100o
120o
125o
130o
150o
Correct answer is D
Since < URP = 25°, then < XPU = 4 x 25° = 100°
\(\therefore\) < TPQ = 180° - 100° = 80°
\(\therefore\) < PQT = 180° - (80° + 25°) = 75°
< SQR = 75° - 25° = 50° (exterior angle = 2 opp interior angles)
\(\therefore\) < USQ = 180° - 50° = 130°
Similar Questions
Find the equation whose roots are \(-\frac{2}{3}\) and 3...
Given that log\(_3\) 27 = 2x + 1, find the value of x....
Evaluate \(\frac{(3.2)^2 - (4.8)^2}{3.2 + 4.8}\)...
If cos\(\theta\) = \(\frac{a}{b}\), find 1 + tan2\(\theta\)...
If x + 1 is a factor of x3 + 3x2 + kx + 4, find the value of k...
The nth term of a sequence is n2 - 6n - 4. Find the sum of the 3rd and 4th terms....
In this fiqure, PQ = PR = PS and SRT = 68\(^o\). Find QPS ...