WAEC Past Questions and Answers - Page 1201

6,001.

Find the distance between the points (2, 5) and (5, 9).

A.

4 units

B.

5 units

C.

12 units

D.

14 units

Correct answer is B

Distance between two points (a, b) and (c, d) = \(\sqrt{(d - b)^{2} + (c - a)^{2}}

Distance between (2, 5) and (5, 9) = \(\sqrt{(9-5)^{2} + (5-2)^{2}}\)

= \(\sqrt{16 + 9} = \sqrt{25} = 5 units\)

6,002.

A ball is thrown vertically upwards with a velocity of 15\(ms^{-1}\). Calculate the maximum height reached. \([g = 10ms^{-2}]\)

A.

15.25m

B.

13.25m

C.

11.25m

D.

10.25m

Correct answer is C

Maximum height (H) = \(\frac{u^{2}}{2g}\)

= \(\frac{15^{2}}{2 \times 10} = \frac{225}{20}\)

= \(11.25m\)

6,003.

If the points (-1, t -1), (t, t - 3) and (t - 6, 3) lie on the same straight line, find the values of t.

A.

t = -2 and 3

B.

t = 2 and -3

C.

t = 2 and 3

D.

t = -2 and -3

Correct answer is C

For collinear points (points on the same line), the slopes are equal for any 2 points on the line.

Given (-1, t - 1), (t, t - 3), (t - 6, 3), 

\(slope = \frac{(t-3) - (t-1)}{t - (-1)} = \frac{3 - (t-3)}{(t-6) - t} = \frac{3 - (t-1)}{(t-6) - (-1)}\)

Taking any two of the equations above, solve for t.

\(\frac{t - 3 - t + 1}{t + 1} = \frac{6 -t}{-6}\)

\(12 = (6 - t)(t + 1)\)

\(-t^{2} + 5t + 6 - 12 = 0 \implies t^{2} - 5t + 6 = 0\)

Solving, we have t = 2 and 3. 

6,004.

The depreciation method in which the number of years of the useful life of an asset is allocated in a reverse order is

A.

Straight line

B.

Reducing balance

C.

Sum of the yeara; digits

D.

Revaluation

Correct answer is C

No explanation has been provided for this answer.

6,005.

The art of collecting, recording, presenting and interpreting accounting data is

A.

Cost accounting

B.

Management accounting

C.

Financial accounting

D.

Data processing

Correct answer is C

No explanation has been provided for this answer.