Find the equation of a circle with centre (2, -3) and radius 2 units.
\(x^{2} + y^{2} - 4x + 6y + 9 = 0\)
\(x^{2} + y^{2} + 4x - 6y - 9 = 0\)
\(x^{2} + y^{2} + 4x + 6y - 9 = 0\)
\(x^{2} + y^{2} + 4x - 6y + 9 = 0\)
Correct answer is A
The equation of a circle with centre coordinate (a, b) and radius r is :
\((x - a)^{2} + (y - b)^{2} = r^{2}\)
Given centre = (2, -3) and radius r = 2 units
Equation = \((x - 2)^{2} + (y - (-3))^{2} = 2^{2}\)
\(x^{2} - 4x + 4 + y^{2} + 6y + 9 = 4\)
\(x^{2} + y^{2} - 4x + 6y + 4 + 9 - 4 = 0 \implies x^{2} + y^{2} - 4x + 6y + 9 = 0\)
In the absence of partnership agreement, a loan by a partner attracts interest at
20%
15%
10%
5%
Correct answer is D
No explanation has been provided for this answer.
3
2
-2
-3
Correct answer is D
The sum of deviations from the mean of a set of numbers equals 0.
\((k+3)^{2} + (k+7) + (-2) + k + (k+2)^{2} = 0\)
\((k^2 + 6k + 9) + (k+7) - 2 + k + (k^2 + 4k + 4) = 0\)
\(2k^{2} + 12k + 18 = 0\)
\(2k^{2} + 6k + 6k + 18 = 2k(k + 3) + 6(k + 3) = 0\)
\(k = -3 (twice)\)
\(-45(2i + \sqrt{2}j)\)
\(60(\sqrt{3}i + 7j)\)
\(30(7i + \sqrt{3}j)\)
\(-15(7i + \sqrt{3}j)\)
Correct answer is D
\(F = F\cos\theta + F\sin\theta\)
\(\implies 90N = 90\cos 120° + 90\sin 120°\)
\(120N = 120 \cos 240° + 120 \sin 240°\)
\(R = F_{1} + F_{2} \)
= \((90 \cos 120 + 120 \cos 240)i + (90\sin 120 + 120 \sin 240)j\)
= \(90(-0.5) + 120(-0.5))i + (90(\frac{\sqrt{3}}{2}) + (120(-\frac{\sqrt{3}}{2}))j\)
= \(-105i - 15\sqrt{3}j = -15(7i + \sqrt{3}j)\)
Which of the following is not used for determining working capital?
Cash
Debtors
Motor vehicles
Overdraft
Correct answer is C
No explanation has been provided for this answer.