Express 25° 45' in decimal (Hint: 1° = 60')
25.75o
25.55o
25.45o
25.15o
Correct answer is A
25° 45' = 25° + \(\frac{45}{60}\)°
= 25° + 0.75°
= 25.75°
5.0km
7.5km
7.6km
8.7km
Correct answer is D
\((PR)^2 = (PQ)^2 + (QR)^2\)
\(10^2 = 5^2 + (QR)^2\)
\((QR)^2 = 100 - 25\)
\(QR = \sqrt{75}\)
= \(8.660\)
\(\approxeq\) 8.7 km
Given that sin \(P = \frac{5}{13}\), where p is acute, find the value of cos p - tan p
\(\frac{79}{156}\)
\(\frac{85}{156}\)
\(\frac{7}{13}\)
\(\frac{8}{1}\)
Correct answer is A
If \(sin P = \frac{5}{13}\) from right angled triangle from pythagoras theorem
\(BC^2 = 13^2 - 5^2\\
=169-25\\
BC = \sqrt{144} = 12\\
∴ cos P - tan P = \frac{12}{13} - \frac{5}{12}\\
=\frac{79}{156}\)
The bearing S40°E is the same as
040o
050o
130o
140o
Correct answer is D
= 90° + 50°
= 140°
If 2x : (x +1) = 3:2, what is the value of x?
\(\frac{1}{2}\)
1
\(1\frac{1}{2}\)
3
Correct answer is D
\(2x : (x + 1) = 3:2\\
\frac{2x}{x+1}=\frac{3}{2}\\
∴ 4x = 3x + 3 x =3\)
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