How many different 8 letter words are possible using the letters of the word SYLLABUS?
(8 - 1)!
\(\frac{8!}{2!}\)
\(\frac{8!}{2! 2!}\)
8!
Correct answer is C
SYLLABUS has 8 letters, 2S's and 2L's
\(\frac{8!}{2! 2!}\)
x = 2,3
x = 0,3
x = \(\frac{1}{2}\), \(\frac{1}{3}\)
x = \(\frac{1}{2}\), \(\frac{-1}{3}\)
Correct answer is C
6x\(^2\) = 5x - 1
→ 6x\(^2\) - 5x + 1 = 0
Factorization:
factors are -3x and -2x
6x\(^2\) - 3x -2x + 1 = 0
(6x\(^2\) - 3x) (-2x + 1) = 0
3x(2x-1) -1(2x-1) = 0
(3x-1) (2x-1) = 0
x = \(\frac{1}{2}\), \(\frac{1}{3}\)
Given that log\(_3\) 27 = 2x + 1, find the value of x.
0
1
2
3
Correct answer is B
Recall that: log\(_3\) 27 → log\(_3\)3\(^3\)
3log\(_3\)3 → 3 * 1
= 3
Then log\(_3\) 27 = 2x + 1
→ 3 = 2x + 1
3 - 1 = 2x
2 = 2x
1 = x
3:20
3:17
17:20
20:23
Correct answer is C
Where the loss= (100-15)%
= 85%
Ratio = 85:100 or 17:20
If the equations x\(^2\) - 5x + 6 = 0 and x + px + 6 = 0 have the same roots, find the value of p.
5
6
-5
-6
Correct answer is C
If "x" is the same for both equations, then they are equivalent.
(i.e., the equations have same roots), then the equations are equivalent.
Then p = -5