5cm
7cm
10cm
15cm
Correct answer is C
Area of a trapezium = \(\frac{[a+b]h}{2}\)
105 = \(\frac{[9+12]h}{2}\) → 105 x 2 =21h
h = \(\frac{210}{21}\) → 10cm
72.57cm\(^3\)
88.12cm\(^3\)
10529cm\(^3\)
113.14cm\(^3\)
Correct answer is D
Volume of sphere = \(\frac{4πr^3}{3}\) → \(\frac{4 x 22 x 3^3}{3}\)
= \(\frac{792}{7}\)
= 113.14cm\(^3\)
33.35
35.54
34.45
36.44
Correct answer is C
\(\frac{12 + 47 + 49 + 15 + 43 + 41 + 13 + 39 + 43 + 41 + 36}{11}\)
= \(\frac{379}{11}\)
= 34.45
12
13
15
20
Correct answer is C
Rearranged: 12,13,15, 36, 39, 41, 41, 43, 43, 47 and 49
Lower quartile or First quartile = \(\frac{total number of items}{4}\)
If odd: items numbers + 1 → \(\frac{11 items + 1}{4}\)
= \(\frac{12}{4}\)
Lower quartile = 3rd iems →15
Solve \(\frac{y+2}{4}\) - \(\frac{y-1}{3}\) > 1
y < -10
y < -2
y < 2
y < 10
Correct answer is B
multiply both sides by the LCM
12 x \(\frac{y+2}{4}\) - 12 x \(\frac{y-1}{3}\) >12 x 1
3[y+2] - 4[y-1] > 12
3y + 6 - 4y + 4 > 12
-y + 2 > 12
-y > 12 - 10 = 2
y < -2