90oC
80oC
50oC
40oC
30oC.
Correct answer is A
Final Temperature = \(\frac{m_1 T_1 + m_2 T_2}{m_1 + m_2}\)
where m\(_1\) and m\(_2\) are the weights of the water in the first and second containers.
T\(_1\) and T\(_2\) are the temperatures of the water in the first and second container.
Given Final temperature = 50°C;
Let m\(_1\) = b, then m\(_2\) = 2b.
T\(_1\) = t; T\(_2\) = 30°C
\(\therefore 50 = \frac{b(t) + 2b(30)}{b + 2b}\)
\(50 = \frac{bt + 2b(30)}{3b}\)
\(50(3b) = bt + 2b(30) \implies 150b = b(t + 60)\)
\(150 = t + 60 \implies t = 150 - 60 = 90°C\)
0oC
2/9oC
4/9oC
9/4oC
9/2oC
Correct answer is C
No explanation has been provided for this answer.
0.3600 m
0.1800 m
0.0360 m
0.0036m
0.0018 m
Correct answer is D
No explanation has been provided for this answer.
41.0oC
50.0oC
62.5oC
70.0oC
75.0oC.
Correct answer is E
No explanation has been provided for this answer.
13.0 N
7.0 N
3.3N
3.0N
0.3N
Correct answer is D
No explanation has been provided for this answer.