WAEC Mathematics Past Questions & Answers - Page 304

1,516.

Let U = {1, 2, 3, 4}, P = {2, 3} and Q = {2, 4}. What is (P∩Q)'?

A.

(1, 2, 3)

B.

(1, 3, 4)

C.

(2, 3)

D.

(1, 3)

E.

(1, 4)

Correct answer is B

U = {1,2,3,4}; P = {2,3}; Q = {2,4}; P∩Q = {2} (P∩Q)' = {1,3,4}

1,517.

In the diagram above , |AD| = 10cm, |DC| = 8cm and |CF| = 15cm. Which of the following is correct?

A.

Area BCF = Area DCF

B.

Area ADE = Area ADF

C.

Area ADE = Area DCFE

D.

Area CBF = Area DABC

E.

Area DABO = Area CFEO

Correct answer is E

No explanation has been provided for this answer.

1,518.

In the diagram above , |AD| = 10cm, |DC| = 8cm and |CF| = 15cmIf the area of triangle DCF = 24cm2, find the area of the quadrilateral ABCD.

A.

24cm2

B.

48cm2

C.

80cm2

D.

96cm2

E.

120cm2

Correct answer is B

Area of \(\Delta\)DCF = 24cm2

Area of Quad= 2 x 24 = 48cm2

1,519.

In the diagram above, PQ and XY are two concentric arc; center O, the ratio of the length of the two arc is 1:3, find the ratio of the areas of the two sectors OPQ and OXY

A.

1:3

B.

1:6

C.

1:9

D.

2:3

E.

4:9

Correct answer is C

Let the radius of the arc PQ = r and the radius of the arc XY = R.

Length of arc PQ = \(\frac{\theta}{360} \times 2\pi r = 1\)

Length of arc XY = \(\frac{\theta}{360} \times 2\pi R = 3\)

Ratio of the arc = \(\frac{r}{R} = \frac{360 \times 2\pi \theta}{2\pi \theta \times 360 \times 3}\)

= \(\frac{1}{3}\)

Ratio of their area = \((\frac{1}{3})^2 = \frac{1}{9}\)

= 1 : 9

1,520.

Find the area of an equivalent triangle of side 16cm

A.

64√3cm2

B.

72√3cm2

C.

96cm2

D.

128√3cm2

E.

128cm2

Correct answer is A

Area = 1/2 x 16 x 16sin60o = 64√3cm2