If sinθ = 3/5 find tanθ for 0 < θ < 90o
4\5
3\4
5\8
1\2
3\8
Correct answer is B
sinθ = 3/5
tanθ = 3/4
16o
17o
73o
106o
164o
Correct answer is E
Using pythagoras' theorem:
Hyp\(^2\) = Adj\(^2\) + Opp\(^2\) → 24\(^2\) + 7\(^2\)
Hyp = √625 → 25
\(\tan P = \frac{7}{24}\)
\(\tan P = 0.2917\)
\(P = \tan^{-1} (0.2917)\)
= 16.26°
Bearing of Q from P = 180° - 16.26°
= 163.74° \(\approxeq\) 164°
Points P and Q respectively 24m north and 7m east point R. Calculate |PQ| in meters
20
24
25
31
84
Correct answer is C
No explanation has been provided for this answer.
I & III only
I & IV only
II & III only
II & IV only
All of the above
Correct answer is C
No explanation has been provided for this answer.
What is the difference in longitude between P (lat. 50°N. long. 50°W) and Q (lat.50°N, long. 150°W)?
300o
200o
130o
100o
30o
Correct answer is D
Let \(\theta\) be the angular difference between P (50°N. 50°W), and Q (50°N, 150°W),
\(\theta\) = 150° - 50° =100°