Calculate the mean deviation of 5, 8, 2, 9 and 6
5
4
3
2
Correct answer is D
| x | x - \(\bar{x}\) | (x - \(\bar{x}\)) |
|
5 8 2 9 6 |
-1 2 -4 3 0 |
1 2 4 3 0 |
\(\bar{x}\) = \(\frac{30}{5}\) = 6
\(\sum |x - \bar{x}|\)
= 10
Mean deviation = \(\frac{10}{5}\)
= 2
If the mean of 2, 5, (x + 1), (x + 2), 7 and 9 is 6, find the median.
6.5
6.0
5.5
5.0
Correct answer is C
\(\frac{1 + 5 + x + 6 + x + 2 + 7 + 9}{6}\) = 6
26 + 2x = 36
2x = 36 - 26
2x = 10
x = \(\frac{10}{2}\) = 5
2, 5, 6, 7, 7, 9
Median = \(\frac{6 + 7}{2}\) = 6.5
\(\begin{pmatrix} - \frac{5}{3} &, 0 \end {pmatrix}\)
\(\begin{pmatrix} 0, & - \frac{5}{3} \end {pmatrix}\)
\(\begin{pmatrix} 0, & \frac{5}{3} \end {pmatrix}\)
\(\begin{pmatrix} \frac{5}{3} &, 0 \end {pmatrix}\)
Correct answer is D
y = 8x + 5
m = 8
y = 3x\(^2\) - 2x - 5
\(\frac{dy}{dx}\) = 6x - 2x - 5
\(\frac{6x}{6} = \frac{10}{6}\)
x = \(\frac{5}{3}\)
y = 0
30m
32m
42m
50m
Correct answer is B
h = 96 Tan 30\(^o\) = 55.425
P = \(\frac{55.425}{Tan60^o}\)
= 32m
\(\frac{81}{32}\)
\(\frac{9}{8}\)
\(\frac{1}{4}\)
\(\frac{32}{729}\)
Correct answer is D
ar = \(\frac{2}{9}\) .....(i)
ar\(^3\) = \(\frac{8}{81}\) ......(ii)
\(\frac{ar3}{ar} = \frac{8}{81} \times \frac{9}{2}\)
r\(^2 = \frac{4}{9}\)
r = \(\sqrt{\frac{4}{9}}\)
= \(\frac{2}{3}\)
ar = \(\frac{2}{9}\)
a(\(\frac{2}{3}\)) = \(\frac{2}{9}\)
a = (\(\frac{2}{3}\)) = \(\frac{2}{9}\)
a = \(\frac{2}{9} \times \frac{3}{2}\)
a = \(\frac{1}{3}\)
T\(_r\) = ar\(^5\) = (\(\frac{1}{3}\))(\(\frac{2}{5}\))\(^5\)
= \(\frac{32}{729}\)