Find the value of k if y - 1 is a factor of y3 + 4y2 + ky - 6
-6
-4
0
1
Correct answer is D
if y - 1 is a factor of y3 + 4y2 + ky - 6, then
f(1) = (1)3 + 4(1)2 + k(1) - 6 = 0 (factor theorem)
1 + 4 + k - 6 = 0
5 - 6 + k = 0
-1 + k = 0
k = 1
IN the diagram, |LN| = 4cm, LNM = 90o and tan y = 2/3. What is the area of the ∆LMN?
24cm2
12cm2
10cm2
6cm2
Correct answer is B
\(tan \hspace{1mm}y = \frac{opp}{adj}=\frac{2}{3}\Rightarrow \frac{2}{3}=\frac{
LN}{MN}=\frac{4}{MN}\\
∴ MN = \frac{12}{2}=6\\
Area \hspace{1mm}of \hspace{1mm}\Delta LMN = \frac{1}{2}\times MN\times LN=\frac{1}{2}\times 6\times 4=12cm\)
\(5\frac{1}{2}cm\)
\(4\frac{2}{3}cm\)
\(3\frac{1}{2}cm\)
\(2\frac{1}{3}cm\)
Correct answer is D
\(r=\frac{\theta \times l}{360^{\circ }}\\
r=?, \theta =60^{\circ }\), l = radius of the orginal sector of a circle = 14cm
\(r=\frac{60\times 14}{360}=\frac{7}{3}=2\frac{1}{3}cm\)
2.5cm
3.0cm
3.5cm
4.0cm
Correct answer is D
\(5^{2}=3^{2}+x^{2}\\
25-9=x^{2}\\
16=x^{2}\Rightarrow x=4.0\)
The area of a square field is 110.25m2. Find the cost of fencing it round at N75.00 per meter square
N1,575.00
N3,150.00
N4,734.30
N8,268.75
Correct answer is D
N75.00 x 110.25 = N8,268.75
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