100\(^o\)
120\(^o\)
140\(^o\)
160\(^o\)
Correct answer is A
S\(O\)T = 180\(^o\) - (50 + 50)
= 80\(^o\)
P\(Q\)R = 80\(^o\)
= \(\frac{360^o - 160^o}{2}\) = 100\(^o\)
60x cm\(^2\)
45x cm\(^2\)
30x cm\(^2\)
15x cm\(^2\)
Correct answer is A
New are = (2 x 15) x (2 x \(x\))
= 60cm\(^2\)
70\(^o\)
84\(^o\)
96\(^o\)
156\(^o\)
Correct answer is B
L = \(\frac{\theta}{360} \times 2 \pi r\)
22 = \(\frac{theta}{360} \times 2 \times \frac{22}{7} \times 15\)
\(\theta = \frac{22 \times 360 \times 7}{2 \times 22 \times 15}\)
\(\theta\) = 84\(^o\)
$130,000.00
$128,000.00
$125,000.00
$120,000.00
Correct answer is B
\(\frac{8}{100} \times x + 117,760 = x\)
x - \(\frac{8x}{100} = 117,760
\(\frac{92x}{100} = 117,760\)
x = \(\frac{117,760 \times 100}{92}\)
Selling price = N128,000
Make b the subject of the relation lb = \(\frac{1}{2}\) (a + b)h
\(\frac{ah}{2l - h}\)
\(\frac{2l - h}{al}\)
\(\frac{al}{2l - h}\)
\(\frac{al}{2 - h}\)
Correct answer is A
lb = \(\frac{1}{2} (a + b)h
2lb = ah + bh
2lb - bh = ah
\(\frac{b(2l - h)}{2l - h} = \frac{ah}{2l - h}\)
b = \(\frac{ah}{2l - h}\)
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