WAEC Further Mathematics Past Questions & Answers - Page 45

221.

Simplify \(8^{n} \times 2^{2n} \div 4^{3n}\)

A.

\(2^{-n}\)

B.

\(2^{1 - n}\)

C.

\(2^{n}\)

D.

\(2^{n + 1}\)

Correct answer is A

\(8^{n} \times 2^{2n} \div 4^{3n} = 2^{3n} \times 2^{2n} \div 2^{6n}\)

\(2^{2n + 3n - 6n}\)

= \(2^{-n}\)

222.

Which of the following is a singular matrix?

A.

\(\begin{pmatrix} 1 & 0 \\ 0 & 1 \end{pmatrix}\)

B.

\(\begin{pmatrix} 2 & 1 \\ 3 & 2 \end{pmatrix}\)

C.

\(\begin{pmatrix} 3 & 8 \\ 5 & 16 \end{pmatrix}\)

D.

\(\begin{pmatrix} 0 & 1 \\ 1 & 0 \end{pmatrix}\)

Correct answer is A

No explanation has been provided for this answer.

223.

Simplify \(\frac{^{n}P_{4}}{^{n}C_{4}}\)

A.

24

B.

18

C.

12

D.

6

Correct answer is A

\(^{n}P_{4} = \frac{n!}{(n - 4)!}\)

\(^{n}C_{4} = \frac{n!}{(n - 4)! 4!}\)

\(\frac{^{n}P_{4}}{^{n}C_{4}} = \frac{n!}{(n - 4)!} ÷ \frac{n!}{(n - 4)! 4!}\)

= \(4! = 24\)

224.

A committee of 4 is to be selected from a group of 5 men and 3 women. In how many ways can this be done if the chairman of the committee must be a man?

A.

15

B.

40

C.

70

D.

175

Correct answer is D

From the five(5) men viable for the position of the chairman, one of them must be selected.

This implies; 4 men and 3 women are open for committee membership.  

7 C\(_3\) = \(\frac{7!}{3!(7 - 3)!}\) = 

\(\frac{7⋅6⋅5⋅4⋅3⋅2⋅1}{3.2.1 \times 4.3.2.1}\)

= 35 \(\times\) 5 = 175

225.

The mean age of n men in a club is 50 years. Two men aged 55 and 63 years left the club, and the mean age reduced by 1 year. Find the value of n.

A.

30

B.

20

C.

18

D.

14

Correct answer is B

Let the sum of the men's ages be f, so that

\(\frac{f}{n} = 50 .... (1)\)

Also, \(\frac{f - (55 + 63)}{n - 2} = 50 - 1 = 49 .... (2)\)

From (1), \(f = 50n\)

From (2), \(f - 118 = 49(n - 2) = 49n - 98\)

\(f = 49n - 98 + 118 = 49n + 20\)

\(\therefore f = 50n = 49n + 20\)

\(50n - 49n = n = 20\)