0.0005\(\Omega\)cm
0.0015\(\Omega\)cm
0.0016\(\Omega\)cm
0.0700\(\Omega\)cm
Correct answer is A
e = \(\frac{RA}{L} = \frac{10 \times 0.005}{100} = 0.0005\)
1.8A
1.0A
0.8A
0.3A
Correct answer is B
\(\frac{1}{r} = \frac{1}{r_1} + \frac{1}{r_2}\)
= \(\frac{1}{5} + \frac{1}{20}\)
= \(\frac{4 + 1}{20} = \frac{5}{20}\)
r = \(\frac{20}{5}\)
= 4\(\Omega\)
R = R1 + R2
= 5 + 4
= 9\(\Omega\)
but V = IR
I = \(\frac{V}{R} = \frac{9}{9}\)
= 1A
21\(\mu C\)
3.6\(\mu C\)
4.0\(\mu C\)
4.4\(\mu C\)
Correct answer is A
F = \(\frac{Q^2}{4 \pi \varepsilon_o r^2}\)
I = 9 x 109 x \(\frac{Q^2}{0.2^2}\)
Q = \(\sqrt{\frac{0.04}{9 \times 10^9}}\)
= 2.11 x 10-6
16\(\Omega\)
68\(\Omega\)
106\(\Omega\)
212\(\Omega\)
Correct answer is D
\(X_c = \frac{1}{2 \pi fc}\)
= 2 x 3.142 x 50 x 15 x 10-6
= 212.179\(\Omega\)
electrical energy to mechanical energy
mechanical energy to electrical energy
mechanical energy to chemical energy
electrical energy to thermal energy
Correct answer is A
No explanation has been provided for this answer.