Learn more about the properties, composition, and structure of substances (elements and compounds) with these Chemistry questions and answers. This Test can be used by students preparing for Chemistry in JAMB, WAEC, NECO or Post UTME.
Increase in temperature
Decrease in temperature
Increase in pressure
Addition of O2 into the mixture
Correct answer is A
The reaction is an exothermic reaction (∆H=-197kjmol).
For continual yield of sulphur(IV)oxide, heat must be liberated.
So,increasing the temperature of the reaction will lead to reduction in yield of \(SO_3\) since it favours backward reaction which is endothermic.
Which of the following compounds absorbs moisture from the atmosphere and dissolves in it?
FeCI3
MgSO4.7H2O
Na2SO 4
KCI
Correct answer is A
No explanation has been provided for this answer.
The indicator used in neutralizing CH3COOH and NaOH solution has pH range of
3-5
7-8
8-103
10-12
Correct answer is C
No explanation has been provided for this answer.
Which of the following processes is an endothermic reaction?
Dissolving NH4CI crystals in water
Addition of concentrated H2SO4
Dissolving NaOH pellets in water
Passing SO3 gas into water
Correct answer is A
No explanation has been provided for this answer.
formation
hydration
neutralization
solution
Correct answer is C
No explanation has been provided for this answer.
1.12dm3
2.24dm3
5.6dm3
56.0dm3
Correct answer is C
2NaHCO3(s) \(\rightarrow\) 2Na2CO 3(S) + CO 2(g) + H2O(g)
2 moles of 2NaHCO3(s) produces 22.4dm3 of CO2
0.5 moles of 2NaHCO3 will produce \(\frac{0.5 \times 22.4}{2}\)
= \(\frac{11.2}{2}\)
= 5.6 dm3
0.10mol dm-3
0.20mol dm-3
0.40mol dm-3
2.00mol dm-3
Correct answer is C
\(V_1\) = 80cm3, \(C_1\) = 0.5mol/dm3
\(C_2\) = ? \(V_2) = 20cm3 + 80cm3 = 100cm3
using the dilution formula, \(C_1 V_1 = C_2 V_2\)
0.5 x 80 = \(C_2\) x 100
\(C_2 = \frac{ 40}{100}\) = 0.4mol\(dm^{-3}\)
1.56 x 1023
1.56 x 1022
3.6 x 1023
3.6 x 1022
Correct answer is B
23g of sodium contain 6 x 1023 atoms :. 0.6g of sodium will contain \(\frac{0.6 x 6 x 1023}{23}/) = 1.56 x 1022
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