Test your knowledge of advanced level mathematics with this aptitude test. This test comprises Further Maths questions and answers from past JAMB and WAEC examinations.
0.024
0.336
0.664
0.976
Correct answer is D
\(P(\text{at least one solves the problem}) = 1 - P(\text{none solving the problem})\)
= 1 - (0.4)(0.3)(0.2)
= 1 - 0.024
= 0.976
1 sec and 7 sec
1 sec and 8 sec
2 sec and 5 sec
2 sec and 7 sec
Correct answer is A
\(s = ut + \frac{1}{2}at^{2}\)
\(s = ut - \frac{1}{2}gt^{2}\) (Upward movement against gravity)
\(35 = 40t - \frac{1}{2}10t^{2}\)
\(35 = 40t - 5t^{2}\)
\(5t^{2} - 40t + 35 = 0\)
\(t^{2} - 8t + 7 = 0\)
\((t - 1)(t - 7) = 0 \implies t = \text{1 sec and 7 sec}\)
Given that \(p = 4i + 3j\), find the unit vector in the direction of p.
\(\frac{1}{3}(4i + 3j)\)
\(\frac{1}{3}(3i + 4j)\)
\(\frac{1}{5}(3i + 4j)\)
\(\frac{1}{5}(4i + 3j)\)
Correct answer is D
\(\hat {n} = \frac{\overrightarrow{p}}{|p|}\)
where \(\hat {n}\) is the unit vector in the direction of p.
\(|p| = \sqrt{4^{2} + 3^{2}} = \sqrt{25} = 5\)
\(\hat {n} = \frac{1}{5} (4i + 3j)\)
\(\frac{2}{3}\)
\(\frac{2}{5}\)
\(\frac{1}{3}\)
\(\frac{1}{5}\)
Correct answer is A
For independent events \(P(X \cap Y) = P(X) \times P(Y)\)
\(\frac{2}{15} = \frac{1}{5} \times P(Y)\)
\(P(Y) = \frac{2}{15} ÷ \frac{1}{5} = \frac{2}{3}\)
Simplify \(\frac{^{n}P_{3}}{^{n}C_{2}} + ^{n}P_{0}\)
n - 5
n - 3
2n - 1
2n - 3
Correct answer is D
\(\frac{^{n}P_{3}}{^{n}C_{2}} + ^{n}P_{0}\)
\(\frac{^{n}P_{3}}{^{n}C_{2}} = \frac{n!}{(n - 3)!} ÷ \frac{n!}{(n - 2)! 2!}\)
\(\frac{n!}{(n - 3)!} \times \frac{(n - 2)(n - 3)! 2!}{n!} = 2n - 4\)
\(^{n}P_{0} = \frac{n!}{(n - 0)!} = 1\)
\(\frac{^{n}P_{3}}{^{n}C_{2}} + ^{n}P_{0} = 2n - 4 + 1 = 2n - 3\)