How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
026\(^o\)
045\(^o\)
210\(^o\)
240\(^o\)
Correct answer is D
Cos θ = \(\frac{adj}{hyp}\)
= \(\frac{300}{600}\)
= 0.5
θ = Cos - 10.5
= 60
∠ RPQ = ∠ PQs
So the bearing of P from Q is 180 + 60 = 240\(^o\)
Answer is D
Simplify 25\(\frac{1}{2}\) × 8\(\frac{-2}{3}\)
1\(\frac{1}{4}\)
2\(\frac{1}{4}\)
6
10
Correct answer is A
Using law of indices
25\(\frac{1}{2}\) × 8\(\frac{-2}{3}\)
= √25 x (\(\sqrt[3]{8}\)) -2
= 5 x 2-2
= 5 x \(\frac{1}{2^2}\) =
\(\frac{5}{4}\) = \(\frac{11}{4}\)
Answer is A
Approximate 0.9875 to 1 decimal place.
1.1
1.0
0.9
0.10
Correct answer is B
9 is on one decimal place, the next number to it is 8 which will be rounded up to 1 because it is greater than 5 and then added to 9 to give 10, 10 cannot be written, it will then be rounded up to 1 and added to 0. So the answer is 1.0
Calculate the area of an equilateral triangle of side 8cm
8√3
16
4√3
16√3
Correct answer is D
An equilateral triangle has all sides equal and all angles equal as 600
Area = \(\frac{1}{2}\) absinθ
Area = \(\frac{1}{2}\) x 8 x 8 x sin60
= \(\frac{1}{2}\) x 64 x \(\sqrt{\frac{3}{2}}\)
= 16√3 cm\(^2\)
Which one of the following gives the members of the set A1 n B n C?
Φ
{s}
{t, u}
{y, z}
Correct answer is A
A1 = Elements in the universal set but not in A = {s, w, x, y, z} B = {r, s. t, u} C = {t, u, v, w, x} A1 n B n C = elements common to the three sets = none = empty set = Φ