How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
\(\frac{9}{25}\)
\(\frac{1}{5}\)
\(\frac{6}{25}\)
\(\frac{2}{5}\)
Correct answer is A
Prob. (team scored 4 goals) = Prob. (team scored 7 goals) = \(\frac{3}{25}\)
Hence, probability that a team selected at random scored either 4 or 7 goals;
= \(\frac{6}{25} + \frac{3}{25}\)
= \(\frac{9}{25}\)
The mean of 1, 3, 5, 7 and x is 4. Find the value of x
2
4
6
8
Correct answer is B
Mean = \(\frac{\sum x}{n}\)
4 = \(\frac{1 + 3 + 5 + 7 + x}{5}\)
4 x 5 = 16 + x
20 - 16 = x
4 = x
x = 4
1
2
3
9
Correct answer is A
Using the two - point from
\(\frac{y - y_1}{y_2 - y_1} = \frac{x - x_1}{x_2 - x_1}\)
\(\frac{y - 2}{-2 - 2} = \frac{x - 4}{-8 - 4}\)
\(\frac{y - 2}{-4} = \frac{x - 4}{-12}\)
\(\frac{-12(y -2)}{-4}\) = x - 4
3(y -2) = x -4
3y - 6 = x - 4
3y = x - 4 + 6
3y = x + 2...
By comparing the equations;
3y = px + , p = 1
If M and N are the points (-3, 8) and (5, -7) respectively, find |MN|
8 units
11 units
15 units
17 units
Correct answer is D
|MN| = \(\sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\)
= \(\sqrt{(-3 -5)^2 + (8 - 7)^2}\)
= \(\sqrt{(-8)^2 + (8 + 7)^2}\)
= \(\sqrt{64 + (15)^2}\)
= \(\sqrt{64 + 225}\)
= \(\sqrt{289}\)
= 17 units
\(45^o\)
\(95^o\)
\(84^o\)
\(85^o\)
Correct answer is C
x + 2x + 2x + (x + \(30^o\)) + (x + \(20^o\)) + (x - \(10^o\)) = (2n - 4) x \(90^o\)
8x + 50 \(^o\) - 10\(^o\) = (2 x 6 -4) x 90\(^o\)
8x + 40\(^o\) = 8 x 90\(^o\) = 720\(^o\)
8x = 720\(^o\) - 40\(^o\) = 680\(^o\)
x = \(\frac{680^o}{8}\)
= 85\(^o\)