How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
25cm\(^2\)
24cm\(^2\)
16cm\(^2\)
12cm\(^2\)
Correct answer is B
Area of shaded part = 2 x area of \(\bigtriangleup\)SPQ
= 2 x \(\frac{1}{2}\) 8 x 3 =24cm
Hence, area of the unshaded part of the rectangle = area of rectangle - area of shaded part
= 8 x 6 - 24
= 48 - 24
= 24 cm\(^2\)
110\(^o\)
135\(^o\)
165\(^o\)
225\(^o\)
Correct answer is C
In the diagram,
Thus, m = 2 x 55\(^o\) (is a bisector of obtuse
m = 110\(^o\)
n = \(\frac{1}{2}\) x 110\(^o\) (angle at centre = 2 x angle at circum)
n = 55\(^o\)
m + n = 110 + 55 = 165\(^o\)
Trapezium
Prism
Rectangle
Rhombus
Correct answer is D
No explanation has been provided for this answer.
In the diagram, PR is a tangent to the circle at Q, QT//RS,
40\(^o\)
65\(^o\)
85\(^o\)
95\(^o\)
Correct answer is D
In the diagram,
a = 50\(^o\) (alternate angles)
b\(_1\) + a 35\(^o\) = 180\(^o\) (sum of angles on a straight line)
i.e; b\(_1\) + 50\(^o\) + 35\(^o\)
= 180v
b\(_1\) + 180\(^o\) - 85\(^o\) = 90\(^o\)
But b\(_2\) = \(b_1\) = 95\(^o\) (angles in alternate segement)
<QST = b\(_2\) = 95\(^o\)
Find the value of t in the diagram
63\(^o\)
117\(^o\)
126\(^o\)
234\(^o\)
Correct answer is C
In the diagram,
\(\alpha\) = 180\(^o\) - 177\(^o\) (angles on a straight line)
\(\alpha\) = 63\(^o\)
t = 2 x 63\(^o\) (angle at centre = 2 x angle at circum)
= 126\(^o\)