How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
2x2 -x + 1
2x2 - x -1
2x2 + x + 1
2x2 + x -1
Correct answer is D
by method of long division, we get the answer.
40o
55o
50o
60o
Correct answer is A
Sum of angle at a point = 360o
2x + 3x + 4x = 360
9x = 360
x = \(\frac{360}{9}\)
x = 40o
three times as much
the same
twice as much
half as much
Correct answer is C
Let the speed of the 1st trip be x miles/hr
and the speed of the 2nd trip be 3x miles/hr
Speed = distance/time
∴ Time taken to cover a distance of 50 miles on the 1st trip
= \(\frac{50}{xhr}\)
time taken to cover a distance of 300 miles on the next trip
= \(\frac{300}{3xhr}\)
= \(\frac{100}{xhr}\)
∴the new time compared with the old time is twice as much
Simplify 4\(\sqrt{27}\) + 5\(\sqrt{12}\) − 3\(\sqrt{75}\)
7
− 7
− 7\(\sqrt{3}\)
7\(\sqrt{3}\)
Correct answer is D
4\(\sqrt{27}\) + 5\(\sqrt{12}\) − 3\(\sqrt{75}\)
= 4\(\sqrt{3}\) × 9 + 5\(\sqrt{3}\) × 4 − 3\(\sqrt{3}\) × 25
= 4 × 3\(\sqrt{3}\) + 5 × 2\(\sqrt{3}\) − 3 × 5\(\sqrt{3}\)
= 12\(\sqrt{3}\) + 10\(\sqrt{3}\) − 15\(\sqrt{3}\)
= (12 + 10 − 15)\(\sqrt{3}\)
= 7\(\sqrt{3}\)
23m
25m
20m
22m
Correct answer is C
Capacity = Volume = 3080m3
base diameter = 14m
radius = \(\frac{\text{diameter}}{2}\)
= 7m
Volume of Cylidner = Capacity of cylinder
πr2h = 3080
\(\frac{22}{7}\) × 7 × 7 × h = 3080
h = \(\frac{3080}{22 \times 7}\)
h = 20m