How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
24oC
20oC
34oC
30oC
Correct answer is A
t ∝ h, t = 20, h
t = ? h = 60
t = kh where k is constant
20 = 50k
k = \(\frac{20}{50}\)
k = \(\frac{2}{5}\)
when h = 60, t = ?
t = \(\frac{2}{5}\) × 60
t = 24oC
If y = x Sin x, find \(\frac{dy}{dx}\) when x = \(\frac{\pi}{2}\)
\(\frac{- \pi}{2}\)
-1
1
\(\frac{ \pi}{2}\)
Correct answer is C
y = xsinx
\(\frac{dy}{dx}\) = \(1 \sin x + x \cos x\)
= \(\sin x + x \cos x\)
At x = \(\frac{\pi}{2}\)
= sin\(\frac{\pi}{2}\) + \(\frac{\pi}{2} \cos {\frac{\pi}{2}}\)
= 1 + \(\frac{\pi}{2}\) × 0
= 1
Evaluate (\(\sin\)45º + \(\sin\)30º ) in surd form
\(\frac{\sqrt{3}}{2\sqrt{2}}\)
√3 − \(\frac{1}{2}\)
\(\frac{1}{2}\)√2
1 + \(\frac{\sqrt{2}}{2}\)
Correct answer is D
hypotenuse
sin = \(\frac{1}{2}\)
\(\sin45 = \frac{1}{\sqrt{2}}\)
= \(\frac{2}{2}\)
∴ (sin45 + sin30)
= \(\frac{1}{\sqrt{2}} + \frac{1}{2}\)
= \(\frac{\sqrt{2}}{2}\) + \(\frac{1}{2}\)
= \(\frac{\sqrt{2} + 1}{2}\)
= \(\frac{1 + \sqrt{2}}{2}\)
If two graphs Y = px2 + q and y = 2x2 − 1 intersect at x =2, find the value of p in terms of q
q − \(\frac{8}{7}\)
7 − \(\frac{q}{4}\)
8 − \(\frac{q}{2}\)
7 + \(\frac{q}{8}\)
Correct answer is B
Y = Px2 + q
Y = 2x2 - 1
Px2 + q = 2x2 - 1
Px2 = 2x2 - 1 - q
p = \(\frac{2x^2 - 1 - q}{x^2}\)
at x = 2
P = \(\frac{2(2)^2 - 1 - q}{2^2}\)
= \(\frac{2(4) - 1 -q}{4}\)
= \(\frac{8 - 1 - q}{4}\)
P = \(\frac{7 - q}{4}\)
2.6cm
3.5cm
3.6cm
7.0cm
Correct answer is B
Curved surface area of cylinder = 2πrh
110 = 2 × \(\frac{22}{7}\) × r × 5
r = \(\frac{110 \times 7}{44 \times 5}\)
= 3.5cm