How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
8
6
4
3
Correct answer is B
2x + x = 180o
3x = 180o
x = 60o (exterior angle of the polygon)
angle = \(\frac{\text{total angle}}{\text{number of sides}}\)
60 = \(\frac{360}{n}\)
n = \(\frac{360}{60}\)
n = 6 sides
The value of x + x ( xx) when x = 2 is
16
10
18
24
Correct answer is B
when x=2, we have
\(2 + 2(2^{2})\) = \(2 + 8 = 10\)
The base in which the operation was performed was
6
2
4
5
Correct answer is B
No explanation has been provided for this answer.
Find the sum to infinity of the series
\(\frac{1}{4}\), \(\frac{1}{8}\), \(\frac{1}{16}\),..........
\(\frac{1}{2}\)
\(\frac{3}{5}\)
\(\frac{-1}{5}\)
\(\frac{73}{12}\)
Correct answer is A
Sum to infinity
∑ = arn − 1
= \(\frac{a}{1}\) − r
a = \(\frac{1}{4}\)
r = \(\frac{1}{8}\) ÷ \(\frac{1}{4}\)
r = \(\frac{1}{s}\) × \(\frac{4}{1}\)
= \(\frac{1}{2}\)
S = \(\frac{1 \div 4}{1}\) − \(\frac{1}{2}\)
= \(\frac{1}{4}\) ÷ \(\frac{1}{2}\)
= \(\frac{1}{4}\) × \(\frac{2}{1}\)
= \(\frac{1}{2}\)
16
14
12
10
Correct answer is A
Range = Highest Number - Lowest Number
Mode is the number with highest occurrence
10, 9, 10, 9, 8, 7, 7, 10, 8, 4, 6,, 9, 10, 9, 7, 10, 6, 5
Range = 10 − 4 = 6
Mode = 10
Sum of range and mode = range + mode = 6 + 10
= 16