How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
In the diagram, PQ//RT, QR//Su,
134o
132o
96o
48o
Correct answer is B
In the diagram; a = b = 48o (alternate < S)
x = 180o - b (angles on a str. line)
x = 180o - 48o
= 132o
132o
126o
108o
102o
Correct answer is B
In the diagram; 108° + x + x = 180° (sum of angle in a triangle)
108° + 2x = 180°
x = 180° - 108°
= 72°
x = \(\frac{72^o}{2}\)
= 36°
(Angle between tangent and a chord through the point of contact)
Hence, angle PTN = 90 + 36
= 126°
In the diagram, O is the centre. If PQ//RS and ∠ONS = 140°, find the size of ∠POM.
40o
50o
60o
80o
Correct answer is A
In the diagram above,
∠MNO = 140° and angles on a straight line is 180°
: ∠NMO = (180 - 140)° = 40°
Hence; ∠POM = 40° ( alternate angle ∠S)
14cm
7m
3\(\frac{1}{2}\)m
1\(\frac{3}{4}\)m
Correct answer is C
Volume of rectangular tank = L x B x H
= 2 x 7 x 11
= 154cm3
volume of cylindrical tank = \(\pi r^2h\)
154 = \(\frac{22}{7} \times r^2 \times 4\)
r2 = \(\frac{154 \times 7}{22 \times 4}\)
= \(\frac{49}{4}\)
r = \(\sqrt{\frac{49}{4}} = \frac{7}{2}\)
= 3\(\frac{1}{2}\)m
3.0cm
3.5cm
4.0cm
4.5cm
Correct answer is B
Using V = \(\frac{3}{1} \pi r^2h\),
so, 38\(\frac{1}{2} = \frac{1}{3} \times \frac{22}{7} \times r^2 \times 3\)
\(\frac{77}{2} = \frac{22}{7} \times r^2\)
r2 = \(\frac{77 \times 7}{2 \times 22}\)
r2 = \(\frac{49}{4}\)
Hence, r = \(\sqrt{\frac{49}{4}}\)
= 3\(\frac{1}{2}\)