How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
Which of the following is used to determine the mode of a grouped data?
Bar chart
Frequency polygon
Ogive
Histogram
Correct answer is D
No explanation has been provided for this answer.
Make K the subject of the relation T = \(\sqrt{\frac{TK - H}{K - H}}\)
K = \(\frac{H(T^2 - 1)}{T^2 - T}\)
K = \(\frac{HT}{(T - 1)^2}\)
K = \(\frac{H(T^2 + 1)}{T}\)
K = \(\frac{H(T - 1)}{T}\)
Correct answer is A
T = \(\sqrt{\frac{TK - H}{K - H}}\)
Taking the square of both sides, give
T2 = \(\frac{TK - H}{K - H}\)
T2(K - H) = TK - H
T2K - T2H = TK - H
T2K - TK = T2H - H
K(T2 - T) = H(T2 - 1)
K = \(\frac{H(T^2 - 1)}{T^2 - T}\)
35o
40o
55o
60o
Correct answer is A
In the diagram, QOR + 2m(vertically opposite angles)
So, m + 90° + 2m = 180°
(angles on str. line)
3m = 180° - 90°
3m = 90°
m = \(\frac{90^o}{3}\)
= 30°
substituting 30° for m in
2m + 4n = 200° gives
2 x 30° + 4n = 200°
60° + 4n = 200°
4n = 200° - 60°
= 140°
n = \(\frac{140°}{4}\)
= 35°
\(\frac{1}{3}\)
\(\frac{2}{3}\)
1\(\frac{1}{3}\)
1\(\frac{2}{3}\)
Correct answer is C
\(\frac{\sqrt{2} + \sqrt{3}}{\sqrt{3}}\) = \(\frac{\sqrt{2} + \sqrt{3}}{\sqrt{3}}\) x \(\frac{\sqrt{3}}{\sqrt{3}}\)
= \(\frac{\sqrt{2} \times \sqrt{3} + \sqrt{3} \times \sqrt{3}}{\sqrt{3} \times \sqrt{3}}\)
= \(\frac{\sqrt{6} + 3}{3}\)
= \(\frac{3 + \sqrt{6}}{3}\)
= Hence, (m + n) = 1 + \(\frac{1}{3}\)
= 1\(\frac{1}{3}\)
Tom will be 25 years old in n years' time. If he is 5 years younger than Bade's present age.
(30 - n)years
(20 - n)years
(25 - n)years
(30 + n)years
Correct answer is A
Let Tom's present agr be x.
Then x = 25 - n
If Tom is 5 years younger than Bade, then Bade's present age is x + 5 = 25 - n + 5
= (30 - n)