How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
x2 - x - 3 = 0
x2 - 3x - 1 = 0
x2 - 3x - 3 = 0
x2 + 3x - 1 = 0
Correct answer is B
Given; y = x2 - x - 2, y = 2x - 1
Using y = y, gives
x2 - x - 2 = 2x - 1
x2 - 3x - 2 + 1 = 0
therefore, x2 - 3x - 1 = 0
Adding 42 to a given positive number gives the same result as squaring the number. Find the number
14
13
7
6
Correct answer is C
Let the given positive number be x
Then 4 + x = x2
0 = x2 - x - 42
or x2 - x - 42 = 0
x2 - 7x + 6x - 42 = 0
x(x - 7) + 6(x - 7) = 0
= (x + 6)(x - 7) = 0
x = -6 or x = 7
Hence, x = 7
If m = 4, n = 9 and r = 16., evaluate \(\frac{m}{n}\) - 1\(\frac{7}{9}\) + \(\frac{n}{r}\)
1\(\frac{5}{16}\)
1\(\frac{1}{16}\)
\(\frac{5}{16}\)
- 1\(\frac{37}{48}\)
Correct answer is D
If m = 4, n = 9, r = 16,
then \(\frac{m}{n}\) - 1\(\frac{7}{9}\) + \(\frac{n}{r}\)
= \(\frac{4}{9}\) - \(\frac{16}{9}\) + \(\frac{9}{16}\)
= \(\frac{64 - 256 + 81}{144}\)
= \(\frac{-111}{144}\)
= - 1\(\frac{37}{48}\)
Find the equation whose roots are \(\frac{3}{4}\) and -4
4x2 - 13x + 12 = 0
4x2 - 13x - 12 = 0
4x2 + 13x - 12 = 0
4x2 + 13x + 12 = 0
Correct answer is C
Let x = \(\frac{3}{4}\) or x = -4
i.e. 4x = 3 or x = -4
(4x - 3)(x + 4) = 0
therefore, 4x2 + 13x - 12 = 0
Factorize completely: 6ax - 12by - 9ay + 8bx
(2a - 3b)(4x + 3y)
(3a + 4b)(2x - 3y)
(3a - 4b)(2x + 3y)
(2a + 3b)(4x -3y)
Correct answer is B
6ax - 12by - 9ay + 8bx
= 6ax - 9ay + 8bx - 12by
= 3a(2x - 3y) + 4b(2x - 3y)
= (3a + 4b)(2x - 3y)