How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
the bisector of the straight line joining P and M
an arc of a circle with PM as a chord
the bisector of angle PXM
a circle centre X and radius PM
Correct answer is B
No explanation has been provided for this answer.
The graph of the relation y = x2 + 2x + k passes through the point (2, 0). Find the values of k
zero
-2
-4
-8
Correct answer is D
y = x2 + 2x + k at point(2,0) x = 2, y = 0
0 = (2)2 + 2(20 + k)
0 = 4 + 4 + k
0 = 8 + k
k = -8
If y varies directly s the square root of (x + 1) and y = 6 when x = 3, find x when y = 9
8
7
6
5
Correct answer is A
y \(\alpha\) \sqrt{x + 1}\), y = k\sqrt{x + 1}\)
6 = k\(\sqrt{3 + 1}\)
6 = k\(\sqrt{4}\)
6 = 2k
k = \(\frac{6}{2}\) = 3
y = \(\sqrt{(x + 1)}\)
9 = 3\(\sqrt{(x + 1)}\)(divide both side by 3)
\(\frac{9}{3}\) = \(\frac{3\sqrt{x + 1}}{3}\)
3 = \(\sqrt{x + 1}\)(square both sides)
9 = x + 1
x = 9 - 1
x = 8
Find the values of k in the equation 6k2 = 5k + 6
{\(\frac{-2}{3}, \frac{-3}{2}\)}
{\(\frac{-2}{3}, \frac{3}{2}\)}
{\(\frac{2}{3}, \frac{-3}{2}\)}
{\(\frac{2}{3}, \frac{3}{2}\)}
Correct answer is B
6k2 = 5k + 6
6k2 - 5k - 6 = 0
6k2 - 0k + 4k - 6 = 0
3k(2k - 3) + 2(2k - 3) = 0
(3k + 2)(2k - 3) = 0
3k + 2 = 0 or 2k - 3 = 0
3k = -2 or 2k = 3
k = \(\frac{-2}{3}\) or k = \(\frac{3}{2}\)
k = (\(\frac{-2}{3}\), k = \(\frac{3}{2}\))
If p = (y : 2y \(\geq\) 6) and Q = (y : y -3 \(\geq\) 4), where y is an integer, find p\(\cap\)Q
{3, 4}
{3, 7}
{3, 4, 5, 6, 7}
{4, 5, 6}
Correct answer is C
p = (y : 2y \(\geq\) 6)
2y \(\leq\) 6
y \(\leq \frac{6}{2}\)
y = \(\leq\) 3
and Q = (y : y -3 \(\geq\) 4)
y - 3 \(\geq\) 4
y \(\geq\) 4 + 3
y \(\geq\) 7
therefore p = {3, 4, 5, 6, 7} and Q = {7, 6, 5, 4, 3....}
P\(\cap\)Q = {3, 4, 5, 6, 7}