How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
If 2 log x (3\(\frac{3}{8}\)) = 6, find the value of x
\(\frac{3}{2}\)
\(\frac{4}{3}\)
\(\frac{2}{3}\)
\(\frac{1}{2}\)
Correct answer is A
2 log x (3\(\frac{3}{8}\)) = 6(divide both sides by 2)
\(\frac{2 log_x(3 \frac{3}{8})}{2} = \frac{6}{2}\)
\(\log_x \frac{27}{8} = 3\)
\(\frac{27}{8} = x^3\)
\(x^3 = \frac{27}{8}\)
x = \(\sqrt{\frac{27}{8}}\)
= (\(\frac{27}{8}\))\(\frac{1}{3}\)
= \(\frac{(3^3)^{\frac{1}{3}}}{(2^3)^{\frac{1}{3}}}\)
= \(\frac{3}{2}\)
Which of the following is not a probability of Mary scoring 85% in a mathematics test?
0.15
0.57
0.94
1.01
Correct answer is D
The probability not scoring 85% is = 1 - pro(scoring 85%)
= 1 - \(\frac{85}{100}\) = 1 - 0.85
= 0.15
not scoring would be less than 1
The bearing of Y from X is 060o and the bearing of Z from Y = 060o. Find the bearing of X from Z
300o
240o
180o
120o
Correct answer is B
No explanation has been provided for this answer.
8.60m
7.51m
7.15m
1.19m
Correct answer is C
Tan 50o = \(\frac{h}{6}\)
h = 6 tan 50
= 6 x 1.1917
= 7.1505
= 7.15
If sin x = \(\frac{5}{13}\) and 0o \(\leq\) x \(\leq\) 90o, find the value of (cos x - tan x)
\(\frac{7}{13}\)
\(\frac{12}{13}\)
\(\frac{79}{156}\)
\(\frac{209}{156}\)
Correct answer is C
Sin x = \(\frac{5}{13}\)
0o \(\leq\) x \(\leq\) 90o, (cos x - tan x)
AC2 = AB2 + BC2
132 = 52 + BC2
169 - 25 + BC2
169 - 25 = BC2
144 = BC2
Cos x = \(\frac{Adj}{Hyp}\) = \(\frac{12}{13}\)
BC = \(\sqrt{144}\)
BC = 12
tan x = \(\frac{opp}{adj} = \frac{5}{12}\)
BC = 12
cos x - tan x = \(\frac{12}{13} - \frac{5}{12}\)
\(\frac{144 - 65}{156} = \frac{79}{156}\)