How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
14%
40%
46\(\frac{3}{4}\)%
53\(\frac{1}{3}\)%
Correct answer is C
This histogram is transferred into this frequency table
\(\begin{array}{c|c} Marks & 20 & 40 & 60 & 80 & 100 \\ \hline students & 9 & 7 & 6 & 6 & 2\end{array}\)
Students who scored more than 40 = 6 + 6 + 2 = 14
i.e. \(\frac{14}{30}\) x 100% = 46\(\frac{3}{4}\)%
If PST is a straight line and PQ = QS = SR in the diagram, find y.
24o
48o
72o
84o
Correct answer is A
< PSQ = < SQR = < SRQ = 24o
< QSR = 180o - 48o = 132o
< PSQ + < QSR + y + 180 (angle on a straight lines)
24 + 132 + y = 180o = 156o + y = 180
y = 180o - 156o
= 24o
If PQR is a straight line with QS = QR, calculate TPQ, If QT\\SR and TQS = 3yo
62o
56\(\frac{3}{2}\)o
20\(\frac{3}{2}\)o
18o
Correct answer is C
Since QS = QR
then, angle SQR = angle SRQ
2 SQR = 180 - 56, SQR = \(\frac{124}{2}\) = 62o
QTP = 62o
QTP = 62o, corresponding angle
3y + 56 + 62 = 180 = 3y = 180 - 118
3y = 62 = 180
3y = 180 - 118
3y = 62
y = \(\frac{62}{3}\)
= 20\(\frac{3}{2}\)
In the diagram, HK is parallel to QR, PH = 4cm and HQ = 3cm. What is the ratio of KR:PR?
7:3
3:7
3:4
4:3
Correct answer is B
In \(\bigtriangleup\)PHK and \(\bigtriangleup\)PAR = \(\frac{PH}{PQ} = \frac{PK}{PR}\)
\(\frac{4}{7} \times \frac{PR-KR}{PR}\)
4PR = 7(PR - KR) = 7PR - 7KR
\(\frac{KR}{PR} = \frac{3}{7}\)
KR:PR = 3:7
120o
110o
60o
20o
Correct answer is D
QMN = 60o
MRQ = 60o(angle in the alternate segment are equal)
MQN = 80o(angle sum of a \(\bigtriangleup\) = 180o)
60 = x = 80o(exterior angle = sum of opposite interior angles)
x = 80o - 60o = 20o
RMQ = 20o