How good are you with figures and formulas? Find out with these Mathematics past questions and answers. This Test is useful for both job aptitude test candidates and students preparing for JAMB, WAEC, NECO or Post UTME.
16cm
14cm
12cm
8cm
Correct answer is A
PT x QT = TR x TS
24 x 8 = TR x 12
TR = \(\frac{24 \times 8}{12}\)
= = 16cm
100o
120o
60o
110o
140o
Correct answer is E
In the figure, angle x = 20o + 80o + 40o
= 140o
In the figure, the area of the shaded segment is
3\(\pi\)
9\(\frac{\sqrt{3}}{4}\)
3 \(\pi - 3 \frac{\sqrt{3}}{4}\)
\(\frac{(\sqrt{3 - \pi)}}{4}\)
\(\pi + \frac{9 \sqrt{3}}{4}\)
Correct answer is C
Area of sector = \(\frac{120}{360} \times \pi \times (3)^2 = 3 \pi\)
Area of triangle = \(\frac{1}{2} \times 3 \times 3 \times \sin 120^o\)
= \(\frac{9}{2} \times \frac{\sqrt{3}}{2} = \frac{9\sqrt {3}}{4}\)
Area of shaded portion = 3\(\pi - \frac{9\sqrt {3}}{4}\)
= 3 \(\pi - 3 \frac{\sqrt{3}}{4}\)
The figure is an example of the construction of a
perpendicular bisector of a given straight line QR
perpendicular from a given point to a given line QR
perpendicular to a line from a given point P on that line
given angle
Correct answer is B
QR is a given line and P is a given point. The construction is the perpendicular from a given point P to a given line QR
In the figure, find the value of x
110o
100o
90o
80o
Correct answer is C
Z = X = Y = 180o .........(i)
2Z + Y + Y = 190 = 2Z + 2Y = 180
Z + Y = 90o........(ii)
hence x + (z + y) = 180
x + 90o = 180o
x = 180o - 90o
= 90o